Anyone know ... what the delta-v necessary was?
I’d like to elaborate a little bit on my previous answer. Determining an accurate number is complicated 3-body problem; however, it’s not too hard to come up with a ballpark approximation.
TEI was typically initiated from a 60 nautical mile orbit, or about 111 km. At this altitude, orbital velocity is 1628 m/s and escape velocity is 2303 m/s. Therefore, escaping lunar gravity requires a burn of 2303 – 1628 = 675 m/s. This would place the spacecraft into an Earth orbit approximately equal to the orbit of the Moon. The spacecraft’s velocity relative to the Moon would be 0 and relative to Earth about 1010 m/s. To reach Earth, the spacecraft would have to perform another burn to lower its perigee until it intersects Earth’s atmosphere. Doing so requires the spacecraft to slow down to 182 m/s. After slowing down the spacecraft’s velocity relative to the Moon is 182 – 1010 = –828 m/s.
Fortunately we don’t have to perform two burns as described above. When we burn to escape lunar orbit we don’t have to stop at escape velocity. We can give our spacecraft enough velocity that it will have some speed left over after escaping the Moon’s gravity. The amount of excess velocity that we want the spacecraft to have is the 828 m/s. If we burn in the correct direction, after leaving lunar space the spacecraft will already be going –828 m/s relative to the moon and 182 m/s relative to Earth.
This extra velocity is called
excess hyperbolic velocity, and is given by the formula
V∞
2 = V
bo2 – V
esc2 where V∞ is the excess hyperbolic velocity, V
bo is the burnout velocity, and V
esc is the escape velocity.
We what V∞ to equal 828 m/s and we already know that V
esc is 2303 m/s, therefore
V
bo = (828
2 + 2303
2)
1/2 = 2447 m/s
Since our initial orbital velocity is 1628 m/s, the required ∆v is simply the burnout velocity minus the orbital velocity,
∆v = 2447 – 1628 = 819 m/s
This is approximately the minimum ∆v required to get back to Earth, putting the spacecraft on a trajectory that would take about 5 days to reach Earth. The reason the actual Apollo TEI burns were closer to 1000 m/s was to reduce the travel time to about 3 days.