0% slip and 0% pull coefficient just means that the wheel is driving the weight on it (and no more) without slip
So according to your interpretation of that graph the pull of the vehicle goes
up with increasing slip?!
The numbers for 'pull coefficient' on the y-axis of that graph, as I have already pointed out, represent the proportion of the weight of the vehicle that is acting downslope at those angles, also on the y-axis, i.e. that would be acting to actively oppose the forward motion of the vehicle.
The tests performed got nowhere near showing that the rovers could operate on the moon at all, the wheel failed way before it reached the necessary drawbar pull.
No, it did not.
That drawbar pull will certainly be pertaining to power and not traction, it is worked out on a set speed, so as long as they go slow enough and have enough traction they can do it.
From your source:
For sufficient traction, the tractor must be heavy, and most models can have extra ballast added.
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Doesn't matter. The drawbar pull/weight ratio of the tractor is 75,000/120,000, which is about 0.34. That, according to you, means that vehicle can pull its own mass plus 34% more. An airliner is waaaaay above that, so according to you it should not be able to pull that airliner.
You're not even being consistent with your own arguments.